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PHYS 424 Notes
Part 2
- Chapter 1 [continued]
- Double Slit [continued]
- Low Intensity
- Experimental result
- Decrease intensity of incident light
- Compensate with intensification of signal at screen
- Eventually you see individual flashes on the screen
- Flashes add up to the interference pattern
- Works for light and for electrons and nucleons
- Measurement gives lambda = h / p , where h is Planck's
constant and p is the particle momentum
- Photoelectric effect shows that there is a time
oscillation with angular frequency given by
E= hbar w , where
hbar is Planck's constant / (2 p) and E is
the (free) particle energy.
- Interpretation
- No choice:
- Pattern gives probability of seeing flashes
- To get interference, the probability must be the
square of something wave-like, P = |y|2,
with y =
y1 + y2.
- Time dependence of y
- cos(wt) or sin(wt) fails, because total
probability is time-dependent
- The only other choice is
e±iwt,
which is fine because
| e±iw
t | 2 = 1,
which is time-independent
- Must choose a single sign, since e-iwt +
e+iwt is not time independent.
- Convention is y ~ e-iwt
- Therefore, for a free particle (as in the experiment),
we need to use
y
= A e2 p i x
/ l e-i w t
- In this case
-
- i hbar (d/dx)y
= [2 p hbar
/ l] y
= [h / l] y
= p y
-
i hbar (d/dt)y
= hbar w y
= E y
- There is also the obvious
xy = xy
- We call
- -i hbar (d/dx) the operator p
- i hbar (d/dt) the operator E
- x the operator x [trivial of course]
- Note the sign convention. It is designed
for later consistency with special relativity
- Probability
- Discrete possibilities, probability Pi
- S(Pi) = 1
- <f> = S
[fi Pi]
- sf = Ö S
{ [fi - <f>]2 Pi}
- Continuous possibilities, probability P(x)dx
- ò[P(x) dx] = 1, so the number
of events between x and x + dx is dN = P(x) dx.
Emphasize
- <f(x)> = ò [f(x) P(x) dx]
- sf = Ö ò {
[f(x) - <f(x)>]2 P(x) dx}
- Draw picture of a Gaussian distribution and
interpret pictorially
- Some subtleties
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Part
1, 2,
3,
4,
5,
Schedule,
Outline