5.2abc (a) 0.054%
(b) dl
= mlh/(2mp)
= 1.79 x 10 -10 m
(c) 6.8 eV
5.4 (a) A = 1/sqrt(2)
(b) A = 1/2
5.5 (b) Let |nm> be (2/a) sin (npx1 /a) sin (mpx2 /a) Then
| Particle | Label | Wave function | Energy | Degeneracy |
|---|---|---|---|---|
| Distinguishable | 22 | |22> | 8K | nondegenerate |
| 13 | |13> | 10K | 2 | |
| 31 | |31> | 10K | ||
| Symmetric state | 22 | |22> | 8K | nondegenerate |
| 13 | [1/sqrt(2)] [ |13> + |31> ] | 10K | nondegenerate | |
| Antisymmetric state | 13 | [1/sqrt(2)] [ |13> - |31> ] | 10K | nondegenerate |
| 23 | [1/sqrt(2)] [ |23> - |32> ] | 13K | nondegenerate |
5.7 Quoting an answer gives away the whole story, so ask me for the answer if you need it. The normalization constant in (b) and (c) is 1/sqrt(6).
5.33 (a) 27
(b) 10
(c) 1
| Last revised 2005/05/05 |