1.5
(a) A = Öl
(b) <x> = 0, <x2>
= 1/(2 l2)
(c) s
= 1/[lÖ2],
P = e - Ö2
1.7 Answer given in text.
1.8 There is no effect on expectation values.
1.9 (a) A = [2am/(p hbar)]1/4
(b) V(x) = 2 m a2 x2
(c) <x> = 0,
<x2> = hbar/(4am),
<p> = 0,
<p2> = a m hbar
(d) sx
= Ö[hbar/(4am)],
sp
= Ö[a m hbar]
sx sp
= hbar/2. The wave function in this problem is called a "minimum-uncertainty
wave packet."
1.14 (b) J(x,t) = 0 . The wave function in problem 1.8 is of the form (real function of x) e-iwt, and it is easy to see that when Y is in this form, J must vanish identically.
1.15 P(t) = P(0) e - 2 G t / hbar
Last revised 2002/08/09 |