It works as a kinase to phosphorylate the CTD of RNA pol II, allowing it to clear the promoter complex.
It works as a helicase to melt the ds DNA at the promoter, providing the template for RNA pol II to begin the transcript.
2.
A. If a gene was transcribed in cell type A but not B, what would you expect the results would be if you performed a DNAse sensitivity assay on the DNA region containing the gene in both cell types. (5 pts)
The chromatin structure around the gene in cell type A would be be looser and therefore you would see increasing susceptibility to DNAse digestion as concentrations of DNAse increased. Even at fairly low levels of DNAse, the fragment containing the gene would disappear from a Southern blot result. The chromatin structure around the gene from cell type B would be more densely packed and less accessible to DNAse. Even at high DNAse concentrations, the fragment containing the gene would be present on a Southern blot result.
B. Describe two types of regulatory proteins that help decondense chromatin during transcription initiation. (6 pts)
Histone acetylases attach acetyl groups to lysines
in the
NH2 termini of histone proteins, loosening the attraction between the
protein
and the negatively charged DNA.
Chromatin remodeling complexes act to “push” the DNA out through the histone octamer, loosening the more compacted chromatin structure by phasing the nucleosomes out into a looser configuration.
It is transcribed early, near the 5’ end region of the transcript. It forms a stem-loop structure that binds to tat (an HIV protein) and the cellular protein cyclin T. This recruits cdk9 which hyperphosphoryltes the CTD of RNA pol II, allowing it to continue transcription. Additional cellular factors are also involved but you are not required to name these.
For A, see Figure 8-15. For B, see Figure 8-3.
This is the change in the nucleotide sequence of an RNA transcript. Our example was the apoB transcript. In liver cells, the transcript is not edited and gives rise to a longer form of the protein, apoB-100. In intestinal cells, an enzyme is active that deaminates a C to a U at one codon. This changes the codon into a stop codon. The protein derived from this edited transcript is shorter, apoB-48.
Only once the poly-A tail has been added will a phosphatase, Glc7, bind to the complex of proteins associated with the RNA transcript. It removes a phosphate group from another protein, Npl3 (an SR protein). This allows the exporter, TAP/Nxt1 to bind and allow the complex to diffuse through the nuclear pores to the cytoplasm. Then, a different kinase, Sky1 phosphorylates Np13 again, causing the dissociation of Glc7 and the exporter, allowing it to return to the nucleus with the help of an importer.
Radioactive filter?
Codon
labeled amino acid
No CUU phenylalanine
No CGA proline
Yes CUU leucine
No CCC arginine
Yes CGA arginine
Yes CCC proline
No CUU arginine
No CGA leucine
CUU codes for leucine, CGA codes for arginine, and CCC codes for proline. The other codons do not code for the amino acid that was labeled.
Wobble is the stable non-Watson-Crick base pairing that can occur between anticodon position 1 and codon position 3. Since this allows tRNAs that have such anticodons to remain associated with a codon during translation, the genetic code has become degenerate regarding codons that can associate with such anticodons. The third base of the codon is irrelevant in these codons so that the amino acid being specified by the codon will be the same no matter if the third base is participating in a wobble relationship or not. This prevents incorrect amino acids that might otherwise be carried on these tRNAs from being incorporated during translation.
The enzyme first binds to the amino acid and ATP. Then it catalyzes the hydrolysis of the bond between the alpha and beta phosphates, releasing PP and AMP. It uses the energy released to attach AMP to the COOH of the amino acid. It then flips this to a proofreading site.If incorrect, it releases the complex and tries again. If correct, the enzyme binds to the tRNA and then hydrolyzes the bond between the AMP and the amino acid, using the energy released to attach the amino acid the 3’ end of the tRNA at either the 2’ or 3’ OH of the ribose component.
The tRNA/eEF1-alpha-GTP complex randomly enters
the A site
of the ribosome. At first, only the anticodon side enters while the
amino acid
side cannot enter due to steric hindrance from the attached eEF1-alpha.
If
there are 3 stable hydrogen bonding interactions between the codon at
the A
site and the entering anticodon, the complex will remain there long
enough for
the GTP to hydrolyze to GDP. The eEF1-alpha GDP will no longer be able
to
remain attached to the tRNA and will leave, releasing the amino acid
side from
the steric hindrance. It will then be able to stably engage with the A
site,
using the energy that was released by the GTP hydrolysis. Peptidyl
transferase
activity would then be activated. If, however, an incorrect tRNA had
entered,
there would be insufficient hydrogen bonding between codon and
anticodon and
the complex would be knocked out of the A site before any GTP
hydrolysis could
occur.
Refer to figure 4-24 in the text.
Refer to figure 8-31 in the text.