51. Proof
52. The EMF is called V in these answers; the text's answer for I2 in part (c) has the wrong sign.
Part | I1 | I2 |
---|---|---|
(a) t=0, switch closed | V/( R1 + R2 ) | V/( R1 + R2 ) |
(b) t=infinity, switch closed |
R2 + R3 V ----------------- R1(R2 + R3) + R2R3 |
R3 V ----------------- R1(R2 + R3) + R2R3 |
(c) t=new 0, switch reopened | 0 |
R2 - V ----------------- R1(R2 + R3) + R2R3 |
(d) t=infinity, switch reopened | 0 | 0 |
53.
(a) V / L1 and V / L2 , respectively
(b) V / R
54. In this answer e=2.71828..., not q electron.
L V2 (a) W = ---- Energy supplied by battery. e R2 L V2 (b) WR = - ---- ( 1 - 4/e + 1/e2 ) Energy dissipated in resistor. 2 R2 L V2 (c) WL = ---- ( 1 - 2/e + 1/e2 ) Energy stored in inductor 2 R2 Try adding WR and WL . What explains the result?
Last revised 1998/04/27 |