HRW p. 93 # 69. Solution Diagram Unable to load picture N and S mark the north and south poles, respectively. Theta is, of course, necessarily 40 degrees. r is the distance from a point on the 40-degree latitude circle to the rotation axis of the earth. Quantities Given and Needed 6 Radius of the earth R6.37.10.m (see table on front cover) p 40. Theta q 180 Radius of latitude circle rR.sin(q) Circumference of latitude c2.p.r [r, not R] circle velocity of person on v =? latitude circle Acceleration of person on a wanted latitude circle Techniques The person is being carried around a circle by the rotation of the earth. Hence we need to analyze the centripetal acceleration in circular motion. To do this we need the speed, which is given by the distance travelled divided by the time [definition of speed]. But the distance travelled is once around the circle per day. So The person is being carried around a circle by the rotation of the earth. Hence we need to analyze the centripetal acceleration in circular motion. To do this we need the speed, which is given by the distance travelled divided by the time [definition of speed]. But the distance travelled is once around the circle per day. So Details 2 v a rR.cos(q) r r v2.p. 1.day Hence 2 r 2.p. 1.day a r 2R.cos(q) a4.p. 2 day 2 m a=0.03msec compared to g9.8. ; reasonable in size. 2 sec