Solutions for Problem Set 3

Last revised 1999/09/24

HRW pp. 28-35 #24, 28, 57, 58 diagram, 72
HRW pp. 72-80 # 38 diagram, 53 diagram, 54, 56
Sheet # IV
Files referenced

A number of the solutions, both for this week and for future sets, were first generated using MATHCAD, which includes parts of the MAPLE symbolic-algebra package. You should learn to use one of the packages as soon as possible, preferably the one used in your math classes. I find version 8 of MATHCAD very powerful but somewhat unintuitive and difficult to use. If you choose to learn MATHCAD, you might prefer to use an earlier version.


Problem 28 (Chapter 2)

Diagram

[The diagrams were generated with MATHCAD.]

Techniques

Since x is given as x(t) = 20 t - 5 t3 , v and a can be obtained by differentiation. The results,

v(t) = 20 - 15 t2

a(t) = - 30 t

are plotted above, and the numerical results requested are readily obtained.

Details

(a) v = 0 implies 20 - 15 t2 = 0 so that t = (2/3) sqrt(3) or t = - (2/3) sqrt(3)

(b) a=0 implies - 30 t = 0, so t = 0

(c) From the graph, a(t)<0 when t>0, and a(t)>0 when t<0.

(d) The graphs are shown above.


Problem 57 (Chapter 2)

[Copy of a solution done using MATHCAD]

Diagram

Quantities Given and Needed

Techniques

Details


Check




Problem 58 (Chapter 2)

[Diagram only]

Diagram

Quantities Given and Needed

Techniques

Details


Problem 72 (Chapter 2)

[Copy of a solution done using MATHCAD]

Diagram

[Figure 2-27 in the text]

Techniques

Quantities Given and Needed

Details


Problem 38 (Chapter 4)

Diagram

Quantities Given and Needed

Techniques

Details


Problem 53 (Chapter 4)

Diagram

Quantities Given and Needed

Techniques

Details


Problem 54 (Chapter 4)

Diagram


Quantities Given and Needed


Techniques


Details




Problem 56 (Chapter 4)

[Copy of a solution done using MATHCAD]

Diagram

Quantities Given and Needed


Techniques


Details






Problem IV

Diagram

Quantities Given and Needed

Velocity of water in river vr , known
Magnitude of velocity of boat relative to water vb , known
Rowing angle theta, known
Velocity of boat relative to bank vtot
Time of travel T
Total distance travelled d
Width of river w = dx , known
Distance down the river y = dy , requested

Techniques

There are two physical situations involved: a relative velocity problem to get the speed of the rower relative to the bank, and unaccelerated one-dimensional motion in the direction of the river and the direction perpendicular to the river. Taking y along the river, positive downward, and taking x perpendicular to the river, we have

vtot = vr + vb

y = y0 + vtot, y t

w = x0 + vtot, x t

and if the origin is placed where he started rowing, x0 = 0 and y0 = 0 .

Details

Looking at the diagram, we see that

vr, x = 0 and vr, y = vr

vb, x = vb cos(theta) and vb, y = vb sin(theta)

If we use these results and substitute for vtot in terms of vr and vb , our working equations are

w = vb [cos (theta)] T

y = [vr + vb sin (theta)] T

The first of these gives

T = w / [vb cos (theta)]       (b) answer

and the value of T may be substituted into the second equation to give

y = w [vr + vb sin (theta) ] / [vb cos (theta) ]       (a) answer


Image files referenced:
2-28a
2-57a, 2-57b, 2-57c, 2-57d, 2-57e, 2-57f, 2-57g
2-58a
2-72b, 2-72c, 2-72d, 2-72e
4-38a
4-53a
4-54a
4-54b, 4-54c, 4-54d, 4-54e
4-56a, 4-56b, 4-56c, 4-56d, 4-56e, 4-56f, 4-56g
IV